Obtaining EF record link or recordGUID from file system path

EagleFiler
,
1

Hi,

I’m currently looking into opening an eaglefiler record automatically from a shell script, given the corresponding file or folder’s full path and the name of the library.

In particular, I’d like to look up a record’s eaglefiler recordGUID using the record’s underlying file path, then open the record from my script via the special eaglefiler URL syntax.

What would be the best way to find a record’s eaglefiler recordGUID based on library name and full file system path?

2

You can use AppleScript to look up a record by path (library record whose file is "…") and to get the record link or GUID.

3

Great, thanks for the quick reply! Will check this out.

4

Here’s a more complete example for you. If you save a lookup.applescript file like this:

on run _argv
	set _path to item 1 of _argv
	set _file to POSIX file _path
	tell application "EagleFiler"
		tell library document 1
			set _record to first library record where its file is _file
			return _record's URL
		end tell
	end tell
end run

You can run it from your shell script like this:

osascript lookup.applescript /Users/you/Documents/EFLibrary/Files/folder/file.pdf

to get the x-eaglefiler URL.

1 Like
5

Great, thanks, it works!